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Asked by payton

calculate the mass of sulfur in 6.0 g of Iron (III) sulfate
14 years ago

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Answered by DrBob222
iron(III) sulfate = Fe2(SO4)3
6.0g/molar mass Fe2(SO4)3 = moles Fe2(SO4)3.
moles S = 3 times that.
grams S = moles S x atomic mass S.
14 years ago
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calculate the mass of sulfur in 6.0 g of Iron (III) sulfate

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