Asked by payton
calculate the mass of sulfur in 6.0 g of Iron (III) sulfate
Answers
Answered by
DrBob222
iron(III) sulfate = Fe2(SO4)3
6.0g/molar mass Fe2(SO4)3 = moles Fe2(SO4)3.
moles S = 3 times that.
grams S = moles S x atomic mass S.
6.0g/molar mass Fe2(SO4)3 = moles Fe2(SO4)3.
moles S = 3 times that.
grams S = moles S x atomic mass S.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.