Asked by Kee
Calculate the density of sulfur hexafluoride gas at 800 torr and 35
Answers
Answered by
bobpursley
density=mass/volume=( moles/molmass )/volume
moles/volume from PV=nRT n/v=P/RT
density= P/RTV
moles/volume from PV=nRT n/v=P/RT
density= P/RTV
Answered by
Doc48
From PV = nRT = (mass/f.wt)RT => (mass/Volume) = P(f.wt.)/RT = Density
P = 800 Torr = 1.053 Atm (must convert Torr to Atm b/c R-value units = L∙Atm/mole∙K)
f.wt = S + 6F = [32 + 6(19)] g/mol = 146 g/mol
R = 0.08206 L∙Atm/mole∙K
T = 35ᵒC + 273 = 308 K
D = (1.053-Atm)(146 g/mol)/(0.08206 L∙Atm/mole∙K)(308 K) = 6.08 g/L
P = 800 Torr = 1.053 Atm (must convert Torr to Atm b/c R-value units = L∙Atm/mole∙K)
f.wt = S + 6F = [32 + 6(19)] g/mol = 146 g/mol
R = 0.08206 L∙Atm/mole∙K
T = 35ᵒC + 273 = 308 K
D = (1.053-Atm)(146 g/mol)/(0.08206 L∙Atm/mole∙K)(308 K) = 6.08 g/L
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