Asked by TraiShaun
A ladder 8 meters long is leaning against a wall. If the top of the ladder is slipping down at the rate of 8 meters per second, how fast is the bottom moving away from the wall when it is 7 meters from the wall?
Please give your answer in , enter it without the units.
Please give your answer in , enter it without the units.
Answers
Answered by
Steve
When the ladder base is 7m from the wall, the top is √(64-49) = √15 from the ground.
When the base is x meters from the wall,
x^2 + h^2 = 64
2x dx/dt + 2h dh/dt = 0
2(7)dx/dt + 2√15 (-8) = 0
dx/dt = 16√15/14 = 4.43m/s
When the base is x meters from the wall,
x^2 + h^2 = 64
2x dx/dt + 2h dh/dt = 0
2(7)dx/dt + 2√15 (-8) = 0
dx/dt = 16√15/14 = 4.43m/s
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.