Asked by ADAM
A ladder 12 meters long is leaning against the wall of a building. The bottom of the ladder is sliding away from the wall at the rate of 1.5 m/s. How fast is the top of the ladder sliding down when it is 3 meters above the ground?
Express your answer in square root form. Include unit of measurement.
Express your answer in square root form. Include unit of measurement.
Answers
Answered by
mathhelper
Almost every Calculus textbook I have seen has a variation of this
question as one of the examples to introduce "Rates Of Change"
foot of ladder from wall ---- x m
height of ladder up the wall ---- y m
x^2 + y^2 = 12^2
2x dx/dt + 2y dy/dt = 0
given: dx/dt = 1.5 m/s
find : dy/dt when y = 3
x^2 + 3^2 = 12^2
x = √135
sub into 2x dx/dt + 2y dy/dt = 0
x dx/dt + y dy/dt = 0
√135(1.5) + 3dy/dt = 0
dy/dt = -1.5√135/3 = ..... m/s
question as one of the examples to introduce "Rates Of Change"
foot of ladder from wall ---- x m
height of ladder up the wall ---- y m
x^2 + y^2 = 12^2
2x dx/dt + 2y dy/dt = 0
given: dx/dt = 1.5 m/s
find : dy/dt when y = 3
x^2 + 3^2 = 12^2
x = √135
sub into 2x dx/dt + 2y dy/dt = 0
x dx/dt + y dy/dt = 0
√135(1.5) + 3dy/dt = 0
dy/dt = -1.5√135/3 = ..... m/s
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