Asked by Marion
A large merry-go-round completes one revolution every 17.5 s. Compute the acceleration of a child seated on it, a distance of 5.80 m from its center.
Answers
Answered by
drwls
First compute the angular velocity of the merry-go-round.
w = 2 pi/17.5 = 0.359 radians/s
centripetal acceleration = R w^2
w = 2 pi/17.5 = 0.359 radians/s
centripetal acceleration = R w^2
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