Asked by Anonymous

The second term of a geometric progression is 12 more than the first term given that the common the ratio is half of the first term. Find the third term of the Geometric progression
Answered by Charles
Solution.Tn=ar'n-1 where n=3
Answered by Babalola Joshua
ar = 12 + a (i)
ar^2 = x (ii)
subtract equ (i) from equ (ii)
a = 6
substituting a = 6 into equ (i)
ar = 12 + a
6r = 12 + 6=18
r = 3.
ar'2 = 6 * 3'2
ar'2 = 54
Answered by Assatu
65
Answered by Assatu
ar'2=54
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