Asked by james
The 3rd term of a geometric progression is nine times the 1st term.if the 2nd term is one twenty fourth the 5th term.find the 4th term.(there is a mistake in the 2nd to the last statement.help locate the mistake{final answer 4th term =48).i solved to this extent.ar^2=9 r=3.
Answers
Answered by
Damon
a r^2 = 9 a
so r = 3
ar = (1/24) a r^4
r = (1/24) r^3
24 = r^2 but r = 3, can not be 3 and sqrt 24
a r^3 is fourth term
27 a = ? 48 ?
a = 48/27 ?
I think you have this messed up.
so r = 3
ar = (1/24) a r^4
r = (1/24) r^3
24 = r^2 but r = 3, can not be 3 and sqrt 24
a r^3 is fourth term
27 a = ? 48 ?
a = 48/27 ?
I think you have this messed up.
Answered by
Damon
1 = 1/24 r^3
r^3 = 24
r = 2 sqrt 3
again can not be both
r^3 = 24
r = 2 sqrt 3
again can not be both
Answered by
Anonymous
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