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During a baseball game, a batter hits a pop- up to a fielder 78 m away. The acceleration of gravity is 9.8 m/s2 . If the ball r...Asked by Anonymous
During a baseball game, a batter hits a popup to a fielder 81 m away.
The acceleration of gravity is 9.8 m/s
2
.
If the ball remains in the air for 6.7 s, how
high does it rise?
The acceleration of gravity is 9.8 m/s
2
.
If the ball remains in the air for 6.7 s, how
high does it rise?
Answers
Answered by
drwls
It rises the same distance that an object will fall in 6.7/2 = 3.35 seconds, because that is the time that it will take the ball to fall from maximum height.
H = (1/2)*g*(3.35)^2
H = (1/2)*g*(3.35)^2
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