Question
A boy starts at rest and slides down a frictionless slide as in the figure below. The bottom of the track is a height h above the ground. The boy then leaves the track horizontally, striking the ground a distance d as shown. Using energy methods, determine the initial height H of the boy in terms of h and d.
Answers
h + (d^2)/h
Correction
h + (d^2)/4h
h + (d^2)/4h
H=h+(d^2)/h
H=h+(d^2)/h
\frac{\left(d^2+4h^2\right)}{4h}
mg/(H-h)=1/2mv^2
How are you getting the answers? Pls explain.
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