Asked by Anonymous
Starting at rest, Tina slides down a frictionless waterslide with a horizontal section at the bottom that is 6.10 ft above the surface of the swimming pool and strikes the water a distance of 13.2 ft away from the end of the slide. Using conservation of energy, what is Tina's initial height on the waterslide?
[ ] ft above the bottom of the slide
[ ] ft above the bottom of the slide
Answers
Answered by
oobleck
How long does it take to fall 6.10 ft?
16t^2 = 16.10
Now, knowing t, v at the bottom of the slide is 13.2/t ft/s
the PE lost on the slide is all KE at the bottom. So,
g(h-6.10) = 1/2 v^2
16t^2 = 16.10
Now, knowing t, v at the bottom of the slide is 13.2/t ft/s
the PE lost on the slide is all KE at the bottom. So,
g(h-6.10) = 1/2 v^2
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