Question

1. Carlos jogs in a straight line at a constant speed of 1.5 m/s. He passes by Victoria, who, 10 seconds after Carlos had passed her, starts accelerating at a constant rate of 0.50 m/s^2

a) How much time after the passing of Carlos does it take Victoria to catch up to him?

b) What distance did they travel?

Answer 1

a. d1 = d2,
1.5(t+10) = 0.5*0.5t^2,
1.5t + 15 = 0.25t^2,
-0.25t^2 + 1.5t + 15 = 0,
Use Quad.Formula to find t and get:
t = 11.3s.

b. d = 1.5(11.3+10) = 32m.