Answers by visitors named: Raf

Can someone please post the answer for these questions?

speed = km/h Car speed = 3 km/3hours = 1 km/1hour = 1 km/h

yes I know, it is supposed to give 0/0 and they ask us to manipulate the limit algebraically in order to be able to factorize

and it's the factorization that I can't seem to come up with, thanks for your quick answer too

the question didn't submit well, here's the problem: lim (6-3x)/(((5x+6)^1/2)-4) x->2

tnx Steve! Cheers

I don't understand the question either, that's why I posted it here and that's exactly how the problem is written word by word, so I have really no idea :(. From what I can interpret, is that we're looking for what sum of two numbers m + n would give a minimal value, now 1 number is 2x(m)^2 and the 2nd number is just at n^2. This is what I think it could mean. Thank you for your time.

is it always sinTheta for a force down a plane? Or does it depend on the inclination (left, right)

and what does mu stand for in x*mg*cosTheta*mu ? Thank you for your time!

Okay so from what I understand, I find the elongation from the total Work done on the spring and of course by isolating it in my equation. Sorry if my terms aren't good, I do it in french and try to translate it as good as possible

made a mistake when I wrote Ef = Kf + Ugf instead it's --> Ef = Kf + Ugf + Usf

where Kf is = 0

ohhh I see now, but when you say Work done on spring, you take the Energy formula which is 1/2 k x^2 , wouldn't the work on a spring be mu*N*x?

and why isn't it Wg = Wspring - Wfriction as friction is going to other way?

nevermind my first question, my mistake hehe

okay cool, thanks a lot Bob

how do you find this? 1500*0+5000V=6500V' Thank you for your time

same thing with kinetic friction. I have a question where they ask me to find the work done by friction between the skis and the snow. my answer is: Wf = -Fc * d, but I have a feeling that I need to add the angle to it, or is that only with gravity?

oh and I see what you mean, it's 95 116 J, thanks again!

what is the mistake? And thank you for the information!

and drag and friction work has to be higher at the end than gravity in order to stop the skier at the bottom, right?

I know that I have to use 1/2 mv^2 for the velocity and mgh for gravitational energy, but I'm lost from here, especially when they ask to put it in unit vectors. Thank you

thank you very much!

but the angle will still have no effect right?

thank you

What you do with ln(xy) is just separate it into 2 pieces: ln(x) + ln(y) ln(x) + ln(y) = 1 + y' 1/x + y'/y = 1 + y' 1/x - 1 = y' (1 - y)

Kinetic energy is defined with K = 1/2*m*v^2 so you have Kf - Ki [1/2(m)(vf)^2] - [1/2(m)(vi)^2] = m = mass v = velocity; f for final, i for initial your answer will be in kg * m/s^2 which is the developed way of writing Newtons because 1 kg * m/s^2 = 1 N

il/elle acheter will be il/elle VA acheter je acheterai will be written j'acheterai

the science that deals with the collection, classification, analysis, and interpretation of numerical facts or data, and that, by use of mathematical theories of probability, imposes order and regularity on aggregates of more or less disparate elements.

Electrical conductivity is a physical property. A chemical property involves a change that occurs. However, when electricity passes through an object or substance, no change occurs.

Rise is the change in the y coordinate, if you think of the graph, you are going up or down. Run is the change in the x coordinate, left to right. To find the change, we take the second coordinate, and subtract the first coordinate. So, what does that give us? y2 - (y1) = y change and x2 - (x1) = x change so your slope is y/x, just throw in your numbers now

you have: m1 = 60 kg v1 = 5 m/s m2 = 40 kg v2 = 0 m/s (I presume she's not moving because there's no mention of her velocity) so m1v1 = (m1 + m2)V V = m1v1 / (m1 + m2) solve for v once you find v, you plug it into your kinetic energy formula: K = 1/2mv^2 where you'll have Kf - Ki = your lost energy

tnx for the correction Steve, my bad Sarah

same goes for salts

thanks bob!

Kindly upload solution