Asked by Sam
Man jogs 1.5 m/s.
Dog waits 1.8 s then runs at 3.7 m/s.
How far will they have each travelled when dog catches up to man?
Answer in units of m
Dog waits 1.8 s then runs at 3.7 m/s.
How far will they have each travelled when dog catches up to man?
Answer in units of m
Answers
Answered by
Steve
distances are the same
distance = time*speed
1.5t = 3.7(t-1.8)
t = 3 sec
check:
1.5*3 = 4.5
3.7*1.2 = 4.44
accurate to within rounding
distance = time*speed
1.5t = 3.7(t-1.8)
t = 3 sec
check:
1.5*3 = 4.5
3.7*1.2 = 4.44
accurate to within rounding
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