Asked by Erica
F(x) = cos(x) • the integral from 2 to x² + 1 of
e^(u² +5)du
Find F'(x).
When i did this, i got:
-2xsin(x)e^((x²+1)² + 5)
But my teacher got:
-sin(x) • the integral from x² + 1 of e^(u² +5)du + 2xcos(x)e^((x²+1)² + 5)
Do you know why the integral is in his answer? I'm not sure where I went wrong. If you could help, I would greatly appreciate it. Thanks!!
e^(u² +5)du
Find F'(x).
When i did this, i got:
-2xsin(x)e^((x²+1)² + 5)
But my teacher got:
-sin(x) • the integral from x² + 1 of e^(u² +5)du + 2xcos(x)e^((x²+1)² + 5)
Do you know why the integral is in his answer? I'm not sure where I went wrong. If you could help, I would greatly appreciate it. Thanks!!
Answers
Answered by
Steve
Leibnitz's Rule explains how to take the derivative of an integral. Take a google for it, or consult your textbook.
Basically, you have a product here. cos(x) * Integral f(x)
d/dx of the product is
-sin(x) * Integral + cos(x) * d/dx(Integral(f))
d/dx(Integral) = Integral(df/dx) = f, evaluated at the limits of integration.
Basically, you have a product here. cos(x) * Integral f(x)
d/dx of the product is
-sin(x) * Integral + cos(x) * d/dx(Integral(f))
d/dx(Integral) = Integral(df/dx) = f, evaluated at the limits of integration.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.