A small fish is dropped by a pelican that is rising steadily at 0.61 m/s.The acceleration of gravity is 9.81 m/s2.

Question

How far below the pelican is the fish after the
3.1 s?

Answer 1

Vi=.61

hf-hi=Vi*t-1/2 g t^2 you are looking for the -(hf-hi) where g=9.81, t=3.1