Asked by Kat

Compute
lim √(3-s)-√(3+s))/s
s→0⁡
Answered by drwls
Use L'Hopital's rule.

Take the ratio of the derivatives of numerator and denominator at s = 0

[-(1/2)/ã(3-s) -ã(1/2)/ã(3+s)]/1 @s=0 =
= -1/ã(3