Asked by Blessig iliya

A lift is used to carry boxes to the top floor of a hotel 20m high.A total weight of 100kg of boxes was caried up in 20second.If the useful output of the engine driving the lift mechanism is 1.2 kilowatt.calculate the efficiency of the engine of the lift mechanism.
Answered by Henry
Fb = mg = 100kg * 9.8N/kg = 980N. = Force of the boxes.

Po = Fb*d / t = 980 * 20 / 20 = 980W. =
Power output.

Eff. = (Po / Pi)* 100%,
Eff. = (980 / 1200) * 100% = 81.67%.
Answered by Ella
Where did 9.8N come about
Answered by Ella
9.80N = 1kg
Answered by Esther
I don't understand the solving
Answered by Mary
Pls I don't understand ur solving
Answered by Anonymous
Thanks I understand
Answered by Benita Christopher
Interesting
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