Asked by gal
You need to lift a 200 kg box 5 meters, but it is too heavy. You decide to push it up an incline that makes a 25 degree angle with the ground. With what force do you need to push the box?
Answers
Answered by
bobpursley
force*distancepushed=force*5
force=200*9.8*5/(5/sin25)=200*9.8*sin25 N
force=200*9.8*5/(5/sin25)=200*9.8*sin25 N
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