Asked by JULIE
THE TOTAL AGE OF GROUP OF PARENTS IS 342.A NEW PARENT AGED 48 JOINS THE GROUP AND THE AVERAGE RISES BY 1. WHAT IS THE ORIGINAL AVERAGE.
Answers
Answered by
SraJMcGin
Please use lower-case letters. Using capital letters, or upper case, in computer language is considered impolite, much like shouting. Besides it is much more difficult to read and most of us will not ruin our eyes by trying to read them.
Sra
Sra
Answered by
Steve
let there be n parents
The average age at first is 342/n
After adding 1 parent and 48 years, the new average is 390/(n+1)
342/n + 1 = 390/(n+1)
342(n+1) + n(n+1) = 390n
342n + 342 + n + n^2 - 390n = 0
n^2 - 47n + 342 = 0
342 = 2*171 = 2*3*57 = 2*3*3*19
(n-38)(n-9) = 0
so there were either
38 parents average 9 years old (not likely), or
9 parents average 38 years old
when a 48-year old joins, there are now 10 parents avg age 39
The average age at first is 342/n
After adding 1 parent and 48 years, the new average is 390/(n+1)
342/n + 1 = 390/(n+1)
342(n+1) + n(n+1) = 390n
342n + 342 + n + n^2 - 390n = 0
n^2 - 47n + 342 = 0
342 = 2*171 = 2*3*57 = 2*3*3*19
(n-38)(n-9) = 0
so there were either
38 parents average 9 years old (not likely), or
9 parents average 38 years old
when a 48-year old joins, there are now 10 parents avg age 39
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.