Asked by Viperhayati
A group of visited paid a total of $380 entrance tickets for a zoo. The entrance ticket for a child cost $4. The entrance ticket for an adult cost twice as much. If there were 10 more adult the childrens, how many adult were there?.
My workout 1 chlid -$4. 1 adult -$4×2twice= $8.
10 more adult $8 ×10 = $80.
My workout 1 chlid -$4. 1 adult -$4×2twice= $8.
10 more adult $8 ×10 = $80.
Answers
Answered by
Anonymous
x is the number of childs, and y is the number of adults. Then
4x+8y = 380
y = x + 10
Solve the system
4x + 8(x+10) = 4x + 8x + 80 =380 =>
12x = 300,
then x = 300/12 = 25.
y = x + 10 = 35
35 adults
4x+8y = 380
y = x + 10
Solve the system
4x + 8(x+10) = 4x + 8x + 80 =380 =>
12x = 300,
then x = 300/12 = 25.
y = x + 10 = 35
35 adults
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