Asked by Anonymous
PERIMETER OF A RECTANGLE IS 32CM AND AREA IS 55CM FIND THE LENGHT.
Answers
Answered by
Reiny
l+w = 16 --> l=16-w
lw=55
w(16-w)=55
16w - w^2=55
w^2-16w+55=0
(w-5)(w-11)=0w=5 or w=11
we have a symmetric solution, that is,
if w=5 , then l=11
if w=11, then l = 5
the rectangle is 5 by 11
usually the longer side is called the length
so the length is 11 cm
lw=55
w(16-w)=55
16w - w^2=55
w^2-16w+55=0
(w-5)(w-11)=0w=5 or w=11
we have a symmetric solution, that is,
if w=5 , then l=11
if w=11, then l = 5
the rectangle is 5 by 11
usually the longer side is called the length
so the length is 11 cm
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