6.23) In a measurement of a man's density he is found to have a mass of 65.0 kg in air and an apparent mass of 1.50 kg when completely submerged in water with his lungs empty.
a. What mass of water does he displace?
b. What volume of water does he displace?
c. Calculate his density.
d. If his lungs capacity is 2.0 liters, is he able to float with his lungs filled with air without treading water?
Note: Guys help me, provide me an answer with solution/formula. Thanks!!!?
2 answers
According to a now deceased physicist and mathematician in Sicily called Archimedes the force up on a body in a fluid is the volume of fluid displaced times the density of the fluid times g.
a. 65-1.5 = 63.5 kg lost = Mass of water disp.
b. M = V*D.
63.5 = V*1000,
V = 0.0635 m^3 = Vol. of water disp. = Vol. of man.
c. M = V*D.
65 = 0.0635*D,
D =
b. M = V*D.
63.5 = V*1000,
V = 0.0635 m^3 = Vol. of water disp. = Vol. of man.
c. M = V*D.
65 = 0.0635*D,
D =
1 answer