Asked by Anonymous
the sum of 13 consecutive integers is 26. what is the largest of the integer
Answers
Answered by
Reiny
look at it as an arithmetic series where
a = ? d = 1 and n = 13
S(13) = (n/2)(2a + (n-1)d)
26 = (13/2)(2a + 12)
4 = 2a + 12
2a = -8
a = -4
term(13) = a + 2d = -4 + 12 = 8
a = ? d = 1 and n = 13
S(13) = (n/2)(2a + (n-1)d)
26 = (13/2)(2a + 12)
4 = 2a + 12
2a = -8
a = -4
term(13) = a + 2d = -4 + 12 = 8
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