Find four consecutive odd integers in which the sum makes 0.
3 answers
-3, -1, 1, 3
x+1=the least
x+3=the first
x+5=the second
x+7=the third
x+1+x+3+x+5+x+7=0
4x+16=0
4x=0-16
4x=-16
Then divide all sides by four (4) for x to stand on its own
After that, it will be
x=-4
x+1=-3
x+3=-1
x+5=1
x+7=3
So the four odd integers are: -3, -1, 1, 3
x+3=the first
x+5=the second
x+7=the third
x+1+x+3+x+5+x+7=0
4x+16=0
4x=0-16
4x=-16
Then divide all sides by four (4) for x to stand on its own
After that, it will be
x=-4
x+1=-3
x+3=-1
x+5=1
x+7=3
So the four odd integers are: -3, -1, 1, 3
x+1=the least
x+3=the first
x+5=the second
x+7=the third
x+1+x+3+x+5+x+7=0
4x+16=0
4x=0-16
4x=-16
Then divide all sides by four (4) for x to stand on its own
After that, it will be
x=-4
x+1=-3
x+3=-1
x+5=1
x+7=3
So the four odd integers are: -3, -1, 1, 3
x+3=the first
x+5=the second
x+7=the third
x+1+x+3+x+5+x+7=0
4x+16=0
4x=0-16
4x=-16
Then divide all sides by four (4) for x to stand on its own
After that, it will be
x=-4
x+1=-3
x+3=-1
x+5=1
x+7=3
So the four odd integers are: -3, -1, 1, 3