Asked by amir
find two consecutive even integers such that 5 more than the first is divided by 2 less than the second, the result is 13/12.
Answers
Answered by
Reiny
let the two integers be x and x+2
<<5 more than the first is divided by 2 less than the second, the result is 13/12>
---> (x+5)/x = 13/12
I will let you solve it.
<<5 more than the first is divided by 2 less than the second, the result is 13/12>
---> (x+5)/x = 13/12
I will let you solve it.
Answered by
bobpursley
(n+5)/(n+2-2)=13/12
Answered by
amir
is it 60 im confused i missed class today so, i really didn't get the whole of the lesson. =)
Answered by
Reiny
yes, the two integers are 60 and 62
Answered by
amir
thanks that's what i got just making sure =]
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