Asked by christopher
Find all values of x in the interval [0, 2π] that satisfy the equation.
6 sin2(x) = 3
6 sin2(x) = 3
Answers
Answered by
Steve
You want sin(x) = 1/sqrt(2) or -1/sqrt(2)
So, select all multiples of π/4 between 0 and 2π
So, select all multiples of π/4 between 0 and 2π
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