Asked by Alex

an object is launched from ground level with an initial velocity of 400 feet per second. To the nearest tenth off a second, how long does it take the object to reach a height off 650 feet?

Answers

Answered by Henry
h = Vo*t + 0.5g*t^2 = 650 Ft,
400t + 16t^2 = 650,
16t^2 + 400t -650 = 0,
Use Quadratic Formula to find t:
t = 1.53s.
Answered by Nigeria

1.3 seconds
Answered by florida
its 1.7 had it in a quiz
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