Asked by Hannie

The hypotenuse of a right triangle measures 10m. One leg of the triangle is 2m longer then the other. Find the lengths of the legs.

How would you solve this equation?

Answers

Answered by drwls
First of all, you have to write the equation. Call the shorter leg of the triangle x.


x^2 + (x+2)^2 = 10^2 = 100

2x^2 + 4x + 4 = 100
x^2 + 2x -48 = 0
(x+8)(x-6) = 0

Solve for x etc
Answered by Hannie
thank you :)
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