Question
The hypotenuse of a right triangle measures 10m. One leg of the triangle is 2m longer then the other. Find the lengths of the legs.
How would you solve this equation?
How would you solve this equation?
Answers
drwls
First of all, you have to write the equation. Call the shorter leg of the triangle x.
x^2 + (x+2)^2 = 10^2 = 100
2x^2 + 4x + 4 = 100
x^2 + 2x -48 = 0
(x+8)(x-6) = 0
Solve for x etc
x^2 + (x+2)^2 = 10^2 = 100
2x^2 + 4x + 4 = 100
x^2 + 2x -48 = 0
(x+8)(x-6) = 0
Solve for x etc
Hannie
thank you :)