Asked by lafeisha
The hypotenuse of a right triangle os 13.0 and one leg is 2.0 units shorter than the other. Find the dimensions of the figure (rounded to the nearest tenth).
Answers
Answered by
mathhelper
longer of the 2 legs .... x
shorter of the 2 legs = x-2
x^2 + (x-2)^2 = 13^2
x^2 + x^2 - 4x + 4 = 169
2x^2 - 4x - 165 = 0
use the quadratic formula to find x, reject the negative answer of x
shorter of the 2 legs = x-2
x^2 + (x-2)^2 = 13^2
x^2 + x^2 - 4x + 4 = 169
2x^2 - 4x - 165 = 0
use the quadratic formula to find x, reject the negative answer of x
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