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A ball is thrown upward. It leaves the hand with a velocity of 13.8 m/s, having been accelerated through a distance of 0.495 m. Compute the ball's upward acceleration, assuming it to be constant.
Whats the upward acceleration?
14 years ago

Answers

bobpursley
vf^2=vi^2+2ad

solve for a.
14 years ago

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