Asked by austin
A ball is thrown upward. It leaves the hand with a velocity of 13.8 m/s, having been accelerated through a distance of 0.495 m. Compute the ball's upward acceleration, assuming it to be constant.
Whats the upward acceleration?
Whats the upward acceleration?
Answers
Answered by
bobpursley
vf^2=vi^2+2ad
solve for a.
solve for a.
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