Asked by Kim

A boy pulls a wagon with a force of 20N on a handle of .50 meters long. The end he holds is .25 meters higher than the end attached to the wagon. What is the magnitude of the horizontal component that acts to pull the wagon forward?
Answered by john
Will someone answer this please. Thank you.
Answered by mason
No haha
Answered by Dino
Divide .25m/.50m for a total of .50
This is sort of like cosθ=adj/hyp=.25/.50=.600

Cos^-1 for .50 and your angle is 60°.

After that do 20N·sin 60°
This is hyp· sin θ

Your answer being 17N
There are no AI answers yet. The ability to request AI answers is coming soon!