Asked by Jenny
Thank you!!
A survey of an urban university (population of 25,450) showed that 750 of 1100 students sampled attended a home football game during the season. What inferences can be made about student attendance at football games?
Using the 99% level of confidence, what is the confidence interval?
a. [0.767, 0.814]
b. [0.0.6550, 0.7050]
c. [0.6659, 0.6941]
d. [0.0.6795, 0.6805]
A survey of an urban university (population of 25,450) showed that 750 of 1100 students sampled attended a home football game during the season. What inferences can be made about student attendance at football games?
Using the 99% level of confidence, what is the confidence interval?
a. [0.767, 0.814]
b. [0.0.6550, 0.7050]
c. [0.6659, 0.6941]
d. [0.0.6795, 0.6805]
Answers
Answered by
economyst
I believe the answer is 'none of the above'
The formula for the confidence interval is:
P +or- Z(99) * sqrt(P*Q/n)
P is the estimated probability of attendence = 750/1100 = .6818
Q = 1-P
n = sample size = 1100
Z(99) is the number of standard deviations away from the mean that 99% of the population fall = 2.575
So Z(99)*sqrt(P*Q/n) = .03616.
So the range should be (.6456, .7180)
The formula for the confidence interval is:
P +or- Z(99) * sqrt(P*Q/n)
P is the estimated probability of attendence = 750/1100 = .6818
Q = 1-P
n = sample size = 1100
Z(99) is the number of standard deviations away from the mean that 99% of the population fall = 2.575
So Z(99)*sqrt(P*Q/n) = .03616.
So the range should be (.6456, .7180)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.