Question

According to one survey, the mean serum cholesterol level for U.S. adults was 195.1, with a standard deviation of 41.5. A simple random sample of 95 adults is chosen. Find the 46 percentile for the sample mean.

Write only a number as your answer. Round to one decimal places.

Answer 1

What exactly is it asking you?

Answer 2

Z = (score-mean)/SEm

SEm = SD/√n

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability
(.46) and its Z score. Insert data into above equations and calculate.