Asked by Dee

Find the equation of the circle that satisfies the given conditions.
Center at the origin and passes through (7, 9)


130 = ?
Answered by Reiny
any circle with centre at the origin has equation
x^2 + y^2 = r^2
simply sub in the point(7,9) to find the value of r^2
Answered by liz
A circle is centered at the point (5, -4) and passes through the point (-3, 2).
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