Question
Find the equation of the circle that satisfies the given conditions.
Center at the origin and passes through (7, 9)
130 = ?
Center at the origin and passes through (7, 9)
130 = ?
Answers
any circle with centre at the origin has equation
x^2 + y^2 = r^2
simply sub in the point(7,9) to find the value of r^2
x^2 + y^2 = r^2
simply sub in the point(7,9) to find the value of r^2
A circle is centered at the point (5, -4) and passes through the point (-3, 2).
Related Questions
write the equation of the circle that satisfies each set of conditions.
the center of the circle...
Find an equation in standard form for the hyperbola that satisfies the given conditions.
Center atβ...
find an equation of a circle that satisfies the given conditions through 3,4 slope 0
Find an equation of a circle that satisfies the given conditions.
Center (β2, β8), radius 10