Asked by Andrea
Find an equation of the circle with center at the origin and passing through (2,-5) in the form of (x-A)^2+(y-B)^2=C where A,B,C are constant.
Answers
Answered by
scott
a circle centered at (h,k) with radius r has the general equation
... (x - h)^2 + (y - k)^2 = r^2
in this case ; h and k are zero (origin) , and ... r^2 = 2^2 + (-5)^2
... (x - h)^2 + (y - k)^2 = r^2
in this case ; h and k are zero (origin) , and ... r^2 = 2^2 + (-5)^2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.