Asked by plshelp
Find an equation of the circle
Center on line y–4=0, tangent x-axis at (–2, 0)
Center on line y–4=0, tangent x-axis at (–2, 0)
Answers
Answered by
oobleck
the radius is 4
the center lies at (-2,4)
(x+2)^2 + (y-4)^2 = 16
the center lies at (-2,4)
(x+2)^2 + (y-4)^2 = 16
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