Asked by Aye
Find the equation of the circle with center on the y axis and has y intercepts at 7 and 3
Answers
Answered by
oobleck
the center is at y = (3+7)/2 = 5
so the radius is r = 7-5 = 2
x^2 + (y-5)^2 = 2^2
so the radius is r = 7-5 = 2
x^2 + (y-5)^2 = 2^2
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