Asked by Tanya

a cylinder of diameter 1cm at 30degree celcius is to slid into a hole on a steel plate. the hole has a diameter of 0.9997 cm at 30 degree celcius. to what temperature must be the plate be heated when steel has the alpha 1.1X10^-5/degree celcius
Answered by Henry
Dia.=0.9997 + 1.1*10^-5 (T-30) = 1.0cm,
0.9997 + 1.1*10^-5T - 33*10^-5 = 1,
1.1*10^-5*T=1 - 0.9997 + 0.00033
1.1*10^-5*T = 6.3*10^-4,
T = 57.3 deg.
Answered by sam
2170.13
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