Asked by john R.
a cylinder has a 3" diameter and a 1-7/8" diameter rod with 800psi.
what is the force output of the cylinder extending and retracting
what is the force output of the cylinder extending and retracting
Answers
Answered by
bobpursley
800*PI*(1 7/8)^2=forceoutput*PI*(3)^2
forceoutput=800*(1 7/8 / 3)^2
forceoutput=800*(1 7/8 / 3)^2
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