Asked by john R.

a cylinder has a 3" diameter and a 1-7/8" diameter rod with 800psi.
what is the force output of the cylinder extending and retracting

Answers

Answered by bobpursley
800*PI*(1 7/8)^2=forceoutput*PI*(3)^2

forceoutput=800*(1 7/8 / 3)^2
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