Asked by Luke Phillips
The coordinates of the vertices of a triangle are A(1,3), B(6,10), and C(11,18). Find the perimeter of the triangle when the coordinates are multiplied by 3.
Answers
Answered by
MathMate
The distance between A and B can be calculated using the distance formula:
distance(A,B)=sqrt((xb-xa)^2+(yb-ya)^2)
=sqrt((1-6)^2+(3-10)^2)
=sqrt(25+49)
=sqrt(74)
=8.602 approx.
You can find similarly the distances BC and CA.
Add up the sum AB+BC+CA which is the perimeter of the original triangle.
For the triangle with coordinates 3 times shown, multiply the original perimeter by 3.
distance(A,B)=sqrt((xb-xa)^2+(yb-ya)^2)
=sqrt((1-6)^2+(3-10)^2)
=sqrt(25+49)
=sqrt(74)
=8.602 approx.
You can find similarly the distances BC and CA.
Add up the sum AB+BC+CA which is the perimeter of the original triangle.
For the triangle with coordinates 3 times shown, multiply the original perimeter by 3.
Answered by
logan
Triangle IJK has the coordinates listed :
I (5 , -8) J (10 , -8) K (7 , 4)
Where is J' after a reflection over the y-axis?
I (5 , -8) J (10 , -8) K (7 , 4)
Where is J' after a reflection over the y-axis?
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