Asked by Roberty
                The coordinates of the vertices of ABC are A(-2,2) B (5, -3) and C (-4,-1) Identify the perimeter of ABC. Round each length to the nearest tenth before adding.
I am totally lost!
            
        I am totally lost!
Answers
                    Answered by
            Steve
            
    Review your length formula. Find the lengths of the sides, and add them up. I'll give you one side, you do the other two.
AB = √((5-(-2))^2+(-3-2)^2) = √(7^2+5^2) = √74
    
AB = √((5-(-2))^2+(-3-2)^2) = √(7^2+5^2) = √74
                    Answered by
            DeAndre
            
    find the perimeter of the figure with the given vertices. round to the nearest tenth. D(0,1), E(5,4), and F(2,6)
    
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