Asked by Lauren Marie
A ball is thrown up from a twelve foot platform with an initial velocity of 112 feet/second. The formula that describes the height of the ball in terms of time is: f(t) = -16t^2+112t+12.
Determine the time at which the ball reaches its maximum height. Determine the maximum height of the ball.
Determine the time at which the ball reaches its maximum height. Determine the maximum height of the ball.
Answers
Answered by
Reiny
f'(t) = -32t + 112
= 0 for a max of f(t)
32t = 112
t = 3.5
then f(3.5) = -16(3.5^2) + 112(3.5) + 12
= 208
= 0 for a max of f(t)
32t = 112
t = 3.5
then f(3.5) = -16(3.5^2) + 112(3.5) + 12
= 208
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