Question

ball thrown up from top of 96 foot high tower with initial velocity of 80 ft/s.

when does ball reach max height and how high is it at that time?

Answer 1

v = 80 - 32t
v = 0 is where the ball stops rising and starts falling

0 = 80 - 32t
t = 2.5s

h = 96 + 80t - 16t^2
= 96 + 80*2.5 - 16*6.25
= 196 ft

Answer 2

what is the -32 t? I think I undersaand the rest.