Question

Okay for this question I know I am supposed to use the law of sines. But how can i tell what side is what?

In right triangle ABC, a = 120 and c = 140, and ÐC is the right angle. Solve the triangle. Round to the nearest tenth, if necessary.
bobpursley
angle A is opposite side a.

c/Sin90=a/SinA=b/SinB
of course! thanks!

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