Asked by sonia
Given two spheres, if the volume of the first sphere is 36r, and the volume of the second sphere is 288r, what is the relation of the second radius to the first radius?
Answers
Answered by
Henry
V1 = (4pi/3)r^3 = 36r,
Divide both sides by r:
(4pi/3)r^2 = 36,
Multiply both sides by 3/4pi:
r^2 = 36 * 3/4pi,
r^2 = 27/pi = 8.59,
r = 2.93.
V2 = (4pi/3)r^3 = 288r,
(4pi/3)r^2 = 288,
r^2 = 288(3/4pi) = 216/pi = 68.75,
r = 8.29.
r2/r1 = 8.29/2.93 = 2.83,
r2 = 2.83r1.
Divide both sides by r:
(4pi/3)r^2 = 36,
Multiply both sides by 3/4pi:
r^2 = 36 * 3/4pi,
r^2 = 27/pi = 8.59,
r = 2.93.
V2 = (4pi/3)r^3 = 288r,
(4pi/3)r^2 = 288,
r^2 = 288(3/4pi) = 216/pi = 68.75,
r = 8.29.
r2/r1 = 8.29/2.93 = 2.83,
r2 = 2.83r1.
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