Asked by Anna

If 14.5g of CO2 gas has a volume of 0.13L at 305K , what is its pressure in millimeters of mercury?

I've plugged these values into the equation P=nRT/V but I am having troubles with canceling labels and getting the correct answer. Please explain as much as possible to me!
Answered by DrBob222
Show your work and I'll find the error.
n CO2 = grams/molar mass
Answered by Anna
P= [14.5g*(0.0821L*atm/mol*K)*305K]/0.13L
P=2792.98
P=2792.98*760mmHg = 2122664.8 g/mol*mmHg
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