Asked by Reuben49

Three towns p,Q and R are such that the distance between P and Q is 50km and the distance between p and R is 90km.if the bearing of Q from P is 075 and the bearing of R from p is 310, find the distance between Q and R correct to the nearest Km.
Answered by Reiny
I made a sketch, drew some verticals at Q , P and R to get the bearings entered and found angle P = 125°
so use the cosine law:
QR^2 = 50^2 + 90^2 - 2(50)(90)cos125°
...
....
QR = 125.547... or 126 to the nearest km
Answered by justice psalm
How do you solve it
Answered by Anonymous
Draw the diagram
Answered by Aisha
The distance between q and r 2. Bearing of r from p
Answered by Sadiat
Draw the diagram & solve it.
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