Asked by value

Three towns a, b, and c are such that the distance between a and b is 50km and the distance between a and c is 90km. if the bearing of b from a is 075' and the bearing of c from a is 310'. find the distance between b and c?
Answered by Reiny
I will assume you meant ° for degrees.
angles are measured in degrees, subdivided into 60 minutes, and then again into 60 seconds (just like "time" )

e.g. 34° 12' 35" <--- 34 degrees, 12 minutes, and 35 seconds

Make a sketch
From your description, I have a triangle ABC
with angle A = 125° , AB = 50 and AC = 90

using cosine law:
BC^2 = 50^2 + 90^2 - 2(50)(90)cos 125°
= 10600 - 9000(-.57357..)
= ...

finish it up
Answered by Ifeanyi
291
Answered by Anonymous
how did u solved it pls
Answered by Lazarus Litgwei
Please how did you solve it and got the bearing as 291
Answered by Lazarus Litgwei
Let me see the working
Answered by Aishat
I want to see the diagram
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