Asked by Kelvin
Two towns P and Q lie on the same parallel latitude such that P is due east of Q. When local time at Q is 9.50am , the local time at P is 3.12pm.
( a) Find the longitude difference between P and Q (2mks)
( b) Given that the longitude of P is 52°E , find the longitude of Q (2mks)
( c) A pilot took off from town Q and flew to town P along the parallel of latitude. The pilot took 3 and a quarter hrs travelling at an average speed of 860km per hr to reach P. Calculate to 1dp the latitude of town P and Q if they both lie in the northern hemisphere (3mks)
( d) 2 towns R and S are both on the equator and 3820 nautical miles apart . Town R is due east of town S. Find the local time at R when the local time at S is 2.20pm . ( Take R= 6370km and Pi = 22/7) (3mks)
( a) Find the longitude difference between P and Q (2mks)
( b) Given that the longitude of P is 52°E , find the longitude of Q (2mks)
( c) A pilot took off from town Q and flew to town P along the parallel of latitude. The pilot took 3 and a quarter hrs travelling at an average speed of 860km per hr to reach P. Calculate to 1dp the latitude of town P and Q if they both lie in the northern hemisphere (3mks)
( d) 2 towns R and S are both on the equator and 3820 nautical miles apart . Town R is due east of town S. Find the local time at R when the local time at S is 2.20pm . ( Take R= 6370km and Pi = 22/7) (3mks)
Answers
Answered by
oobleck
(a,b) there are 24 hours in a day, and 360° in a circle, so each hour spans 15° degrees of longitude.
(c,d) let the radius of the earth at the equator be Z. Then the radius of a circle at latitude θ is Z cosθ.
(c,d) let the radius of the earth at the equator be Z. Then the radius of a circle at latitude θ is Z cosθ.
Answered by
geoff
not 100 percent about this but here goes.
9:50am-3:12pm=5:22min=5.36666hrs 24hr=360degrees
(5.36666x360)/24= 80.50degrees difference
9:50am-3:12pm=5:22min=5.36666hrs 24hr=360degrees
(5.36666x360)/24= 80.50degrees difference
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