Asked by Amy
Hi I'm reviewing the following solution in my trigonometry text book and I can't figure out how they got their answer. If someone can help explain how they calculated 542.25 for a^2 (nothing I do comes up with that number):
a2=b2+c2-2bcCosA
a2=(16)^2+(11)^2 -2(16)(11)Cos118
a2=542.25
|a2=|542.25
a=23.3
Thank you!
a2=b2+c2-2bcCosA
a2=(16)^2+(11)^2 -2(16)(11)Cos118
a2=542.25
|a2=|542.25
a=23.3
Thank you!
Answers
Answered by
Reiny
I got exactly that.
a^2= 16^2 + 11^2 - 2(16)(11)cos118°
= 256 + 121 - 352(-.469471562)
= 377 <b>+</b> 165.2539898
= 542.253989
a = √542.2539898
= 23.2863
Are you following the order of operation?
a^2= 16^2 + 11^2 - 2(16)(11)cos118°
= 256 + 121 - 352(-.469471562)
= 377 <b>+</b> 165.2539898
= 542.253989
a = √542.2539898
= 23.2863
Are you following the order of operation?
Answered by
Amy
Thank you, I think it was how I was using my calculator. I didn't add brackets, now I got the same too. Very helpful to have that extra confirmation, I can't tell you how long I've been stuck on this question. Thanks a million!
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